【Django】データベースからソートして値を取得する方法

from django.shortcuts import render
from django.views.generic import ListView
# モデルSampleをインポート
from .models import Sample

class IndexView(ListView):
    template_name = "index.html"
    context_object_name = "records"

    # 整数で「降順」に並べる場合
    queryset = Sample.objects.order_by('-integer_field')

    # 整数で「昇順」に並べる場合
    # queryset = Sample.objects.order_by('integer_field')

from django.shortcuts import render
from django.views.generic import ListView
# モデルSampleをインポート
from .models import Sample

class IndexView(ListView):
    template_name = "index.html"
    context_object_name = "records"

    # 複数フィールドで並び変える
    queryset = Sample.objects.order_by('-boolean_field', 'id')

from django.shortcuts import render
from django.views.generic import ListView
# モデルSampleをインポート
from .models import Sample

class IndexView(ListView):
    template_name = "index.html"
    context_object_name = "records"

    # ソートせず、全件取得
    model = Sample

from django.db import models

# Create your models here.
class Sample(models.Model):
    text_field = models.TextField(
        verbose_name="テキスト"
    )

    boolean_field = models.BooleanField(
        verbose_name="True/False"
    )

    integer_field = models.IntegerField(
        verbose_name="整数"
    )

    datetime_field = models.DateTimeField(
        verbose_name="日時"
    )
    # Metaクラスを作成 
    class Meta:
        ordering = ['-boolean_field']

from django.shortcuts import render
from django.views.generic import ListView
# モデルSampleをインポート
from .models import Sample

class IndexView(ListView):
    sort_id = 1

    if sort_id == 1:
        sort_by = "integer_field"
    elif sort_id == 2:
        sort_by = "boolean_field"
    else:
        sort_by = "id"

    template_name = "index.html"
    context_object_name = "records"

    # sort_byを条件にソート
    queryset = Sample.objects.order_by(sort_by)